| Re: Kinitic Energy is not 1/2mv2 |
| Derek Potter <me@privacy.net> |
| 2007-02-01 12:54:27 |
On Mon, 29 Jan 2007 11:00:06 +0000, Cynic <cynic_999@yahoo.co.uk>
wrote:
> On Sun, 28 Jan 2007 19:25:03 +0000, Derek Potter <me@privacy.net>
> wrote:
>
>
> > > You've missed the sub-thread. In this particular argument, the rate
> > > of consumption is the *given* variable.
> >
> > OK, well we now know the answer is "incoherent".
>
> Well, it was you that made the statement - here it is:
>
> DP:
> > > > Yeah, well it comes to the same thing - depends whether "consumption"
> > > > means total consumption or rate of consumption. Twice the rate, four
> > > > times the total. W(v) is quadratic, like E(v) is quadratic.
>
> Cynic:
> > > Not for a given delta time, no. Twice the rate of consumption equals
> > > twice the amount used over a given time period.
>
> DP:
> > For infinitesimal delta. For the period of acceleration you must
> > integrate. Hence quadratic.
>
> The meaning of your words is that you stated that if fuel is consumed
> at twice the rate (e.g. 2 l/s instead of 1 l/s) then after a given
> time you will use four times the fuel.
No it isn't. You seem to be incapable of understanding plain English.
Or of writing it: "The meaning of your words is that you stated that",
really!
What I said was correct. I set rate and total as different possible
meanings to the word "consumption". I then said "Twice the rate, four
times the total".
> I expect that is not what you meant to say
No, what I meant to say was what I said.
> but read your own words -
> it is what you said. I was disputing that obvious fallacy,
Which doesn't exist anywhere except in your own imagination.
> and you accuse me of being incoherent!
I also accuse you of being illiterate.
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